1var obj={name:"rypy",age:20};
2var obj1=JSON.parse(JSON.stringify(obj));
3obj1.name="rypy1";
4console.log(obj); // {name: "rypy", age: 20}
5console.log(obj1); // {name: "rypy1", age: 20}
6
7php 实现
8echo json_decode($arr);// josn字符串 => 数据结构
9echo json_encode($arr);// 数据结构 => 字符串